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ios – Common Expression in Swift for Alphanumeric

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Your regex checks for one alphanumeric character. It prints 4.

I suppose you wish to examine if there may be any non- alphanumeric character within the string. In that case you need to invert the sample.

func validate(string : String) -> Bool {
    let sample = "[^A-Za-z0-9]"
    guard let vary = str.vary(of: sample, choices: .regularExpression) else {
        return true
    }
    print("substring", String(str[range]))
    return false
}

The operate returns true if all characters within the string are alphanumeric characters, in any other case false.

Alternatively you’ll be able to examine

guard let vary = str.rangeOfCharacter(from: .alphanumerics.inverted) else {

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